How to use the ngram.NGram.compare function in ngram

rewrite still uses the same underlying algorithm"""
        
        # Basic searching of the index
        idx = NGram(self.items)
        self.assertEqual(idx.search('askfjwehiuasdfji'),
            [('askfjwehiuasdfji', 1.0),
             ('asdfawe', 0.17391304347826086),
             ('asfwef', 0.083333333333333329),
             ('adfwe', 0.041666666666666664),
            ])
        self.assertEqual(idx.search('afadfwe')[:2],
                         [('adfwe', 0.59999999999999998), 
                          ('asdfawe', 0.20000000000000001)])
        
        # Pairwise comparison of strings
        self.assertEqual(NGram.compare('sdfeff', 'sdfeff'), 1.0)
        self.assertEqual(NGram.compare('sdfeff', 'zzzzzz'), 0.0)

# Basic searching of the index
        idx = NGram(self.items)
        self.assertEqual(idx.search('askfjwehiuasdfji'),
            [('askfjwehiuasdfji', 1.0),
             ('asdfawe', 0.17391304347826086),
             ('asfwef', 0.083333333333333329),
             ('adfwe', 0.041666666666666664),
            ])
        self.assertEqual(idx.search('afadfwe')[:2],
                         [('adfwe', 0.59999999999999998), 
                          ('asdfawe', 0.20000000000000001)])
        
        # Pairwise comparison of strings
        self.assertEqual(NGram.compare('sdfeff', 'sdfeff'), 1.0)
        self.assertEqual(NGram.compare('sdfeff', 'zzzzzz'), 0.0)

def score_ngram(result, query):
    # TODO: case and accents.
    score = ngram.NGram.compare(result.name, query)
    result.score += score