How to use the kicost.edas.tools.IdenticalComponents function in kicost

hash_fields = {k: fields[k] for k in fields if k not in FIELDS_NOT_HASH and SEPRTR not in k}
        h = hash(tuple(sorted(hash_fields.items())))

        # Now add the hashed component to the group with the matching hash
        # or create a new group if the hash hasn't been seen before.
        try:
            # Add next ref for identical part to the list.
            component_groups[h].refs.append(ref)
            # Also add any manufacturer's part number (or None) and each distributor
            # stock catologue code to the group's list.
            for f in FIELDS_MANFCAT:
                component_groups[h].manfcat_codes[f].add(fields.get(f))
        except KeyError:
            # This happens if it is the first part in a group, so the group
            # doesn't exist yet.
            component_groups[h] = IdenticalComponents()  # Add empty structure.
            component_groups[h].refs = [ref]  # Init list of refs with first ref.
            # Now add the manf. part code (or None) and each distributor stock
            # catologue code for this part to the group set.
            component_groups[h].manfcat_codes = {}
            for f in FIELDS_MANFCAT:
                component_groups[h].manfcat_codes[f] = set([fields.get(f)])
    #print('\n\n\n1++++++++++++++',len(component_groups))
    #for g,grp in list(component_groups.items()):
    #    print('\n', grp.refs)
    #    for r in grp.refs:
    #        print(r, components[r])


    # Now we have groups of seemingly identical parts. But some of the parts
    # within a group may have different manufacturer's part numbers, and these
    # groups may need to be split into smaller groups of parts all having the

# One manf# or cat# that is `None`. Don't split this
                      # group. These parts are not intended to be purchased.
        # CASE FOUR:
        # Otherwise, split the group into subgroups, each with the
        # same manf# and distributors catalogue codes (for that one
        # that will be scraped, the other ones are not considered).
        for i_manfcat in range(max([len(grp.manfcat_codes.get(f)) for f in FIELDS_MANFCAT])):
            manfcat_num = {}
            for f in FIELDS_MANFCAT:
                try:
                    manfcat_num[f] = list(grp.manfcat_codes.get(f))[i_manfcat]
                except IndexError:
                    # If not have more code in the set list, is because just
                    # exist one. So use this as general.
                    manfcat_num[f] = list(grp.manfcat_codes.get(f))[0]
            sub_group = IdenticalComponents()
            sub_group.manfcat_codes = [manfcat_num]
            sub_group.refs = []
            for ref in grp.refs:
                # Use get() which returns `None` if the component has no
                # manf# or distributor# field. That will match if the
                # group manf_num is also None. So append the par to the group.
                if all([components[ref].get(f)==manfcat_num[f] for f in FIELDS_MANFCAT]):
                    sub_group.refs.append(ref)
            new_component_groups.append(sub_group) # Append one part of the split group.
    #print('\n\n\n2++++++++++++++',len(new_component_groups))
    #for grp in new_component_groups:
    #    print('\n', grp.refs)
    #    for r in grp.refs:
    #        print(r, components[r])

    # If the identical components grouped have difference in the `fields_merge`

# One manf# or cat# that is `None`. Don't split this
                      # group. These parts are not intended to be purchased.
        # CASE FOUR:
        # Otherwise, split the group into subgroups, each with the
        # same manf# and distributors catalogue codes (for that one
        # that will be scraped, the other ones are not considered).
        for i_manfcat in range(max([len(grp.manfcat_codes.get(f)) for f in FIELDS_MANFCAT])):
            manfcat_num = {}
            for f in FIELDS_MANFCAT:
                try:
                    manfcat_num[f] = list(grp.manfcat_codes.get(f))[i_manfcat]
                except IndexError:
                    # If not have more code in the set list, is because just
                    # exist one. So use this as general.
                    manfcat_num[f] = list(grp.manfcat_codes.get(f))[0]
            sub_group = IdenticalComponents()
            sub_group.manfcat_codes = [manfcat_num]
            sub_group.refs = []
            for ref in grp.refs:
                # Use get() which returns `None` if the component has no
                # manf# or distributor# field. That will match if the
                # group manf_num is also None. So append the par to the group.
                if all([components[ref].get(f)==manfcat_num[f] for f in FIELDS_MANFCAT]):
                    sub_group.refs.append(ref)
            new_component_groups.append(sub_group) # Append one part of the split group.
    #print('\n\n\n2++++++++++++++',len(new_component_groups))
    #for grp in new_component_groups:
    #    print('\n', grp.refs)
    #    for r in grp.refs:
    #        print(r, components[r])

    # If the identical components grouped have difference in the `fields_merge`

hash_fields = {k: fields[k] for k in fields if k not in FIELDS_NOT_HASH and SEPRTR not in k}
        h = hash(tuple(sorted(hash_fields.items())))

        # Now add the hashed component to the group with the matching hash
        # or create a new group if the hash hasn't been seen before.
        try:
            # Add next ref for identical part to the list.
            component_groups[h].refs.append(ref)
            # Also add any manufacturer's part number (or None) and each distributor
            # stock catalogue code to the group's list.
            for f in FIELDS_MANFCAT:
                component_groups[h].manfcat_codes[f].add(fields.get(f))
        except KeyError:
            # This happens if it is the first part in a group, so the group
            # doesn't exist yet.
            component_groups[h] = IdenticalComponents()  # Add empty structure.
            component_groups[h].refs = [ref]  # Init list of refs with first ref.
            # Now add the manf. part code (or None) and each distributor stock
            # catalogue code for this part to the group set.
            component_groups[h].manfcat_codes = {}
            for f in FIELDS_MANFCAT:
                component_groups[h].manfcat_codes[f] = set([fields.get(f)])
    #print('\n\n\n1++++++++++++++',len(component_groups))
    #for g,grp in list(component_groups.items()):
    #    print('\n', grp.refs)
    #    for r in grp.refs:
    #        print(r, components[r])


    # Now we have groups of seemingly identical parts. But some of the parts
    # within a group may have different manufacturer's part numbers, and these
    # groups may need to be split into smaller groups of parts all having the