How to use the castero.feed.FeedStructureError function in castero
To help you get started, we’ve selected a few castero examples, based on popular ways it is used in public projects.
Secure your code as it's written. Use Snyk Code to scan source code in minutes - no build needed - and fix issues immediately.
xgi / castero / castero / feed.py View on Github 
# channel should have at least 3 children, including a
# title, link, and description tag
channel = root_children[0]
channel_children = list(channel)
if len(channel_children) >= 3:
chan_title_tags = channel.findall('title')
chan_link_tags = channel.findall('link')
chan_description_tags = channel.findall('description')
if len(chan_title_tags) != 1:
raise FeedStructureError(
"RSS feed's channel has too many or too few"
" title tags; expected 1, was: "
+ str(len(chan_title_tags)))
if len(chan_link_tags) != 1:
raise FeedStructureError(
"RSS feed's channel has too many or too few"
" link tags; expected 1, was: "
+ str(len(chan_link_tags)))
if len(chan_description_tags) != 1:
raise FeedStructureError(
"RSS feed's channel has too many or too few"
" description tags; expected 1, was: "
+ str(len(chan_description_tags)))
# if the channel has any items, each item should have
# at least a title or description tag
channel_item_tags = channel.findall('item')
for item in channel_item_tags:
if len(item.findall('title')
+ item.findall('description')) < 1:
raise FeedStructureError(if self._tree.attrib['version'] != '2.0':
raise FeedStructureError("RSS version is not 2.0")
else:
raise FeedStructureError(
"RSS feed does not have a version attribute")
# root should have one child, which is the channel tag
root_children = list(self._tree)
if len(root_children) > 0:
if len(root_children) > 1:
raise FeedStructureError(
"RSS feed has too many children; expected 1, was: "
+ str(len(root_children)))
else:
if root_children[0].tag != 'channel':
raise FeedStructureError(
"RSS feed does not have a channel tag as its child")
else:
# channel should have at least 3 children, including a
# title, link, and description tag
channel = root_children[0]
channel_children = list(channel)
if len(channel_children) >= 3:
chan_title_tags = channel.findall('title')
chan_link_tags = channel.findall('link')
chan_description_tags = channel.findall('description')
if len(chan_title_tags) != 1:
raise FeedStructureError(
"RSS feed's channel has too many or too few"
" title tags; expected 1, was: "
+ str(len(chan_title_tags)))# at least a title or description tag
channel_item_tags = channel.findall('item')
for item in channel_item_tags:
if len(item.findall('title')
+ item.findall('description')) < 1:
raise FeedStructureError(
"An item in the RSS feed's channel did not"
" have at least one of a title or a"
" description tag")
else:
raise FeedStructureError(
"RSS feed's channel does not have enough required"
" children; expected >=3, was: "
+ str(len(channel_children)))
else:
raise FeedStructureError(
"RSS feed does not have any children; expected 1 (a channel"
" tag)")
self._validated = Trueself.menus_valid = False
self.change_status("Feed '%s\' successfully added" % str(feed))
except FeedError as e:
if isinstance(e, FeedLoadError):
self.change_status(
"FeedLoadError: %s" % str(e)
)
elif isinstance(e, FeedDownloadError):
self.change_status(
"FeedDownloadError: %s" % str(e)
)
elif isinstance(e, FeedParseError):
self.change_status(
"FeedParseError: %s" % str(e)
)
elif isinstance(e, FeedStructureError):
self.change_status(
"FeedStructureError: %s" % str(e)
)
else:
self.change_status(
"FeedError [ambiguous]: %s" % str(e)
)- for each child of the channel tag which is an item tag, if any:
- the item tag must have at least one child, which is a title
tag or a description tag
See http://cyber.harvard.edu/rss/rss.html for more details.
This method does not set this object's metadata. That is done in
_process_feed().
Raises:
FeedStructureError: the XML document violates one of the conditions
"""
assert self._tree is not None
# root should be an rss tag
if self._tree.tag != 'rss':
raise FeedStructureError("XML document is not an RSS feed")
# root should have version attribute which equals 2.0
if 'version' in self._tree.attrib:
if self._tree.attrib['version'] != '2.0':
raise FeedStructureError("RSS version is not 2.0")
else:
raise FeedStructureError(
"RSS feed does not have a version attribute")
# root should have one child, which is the channel tag
root_children = list(self._tree)
if len(root_children) > 0:
if len(root_children) > 1:
raise FeedStructureError(
"RSS feed has too many children; expected 1, was: "
+ str(len(root_children)))"RSS feed's channel has too many or too few"
" link tags; expected 1, was: "
+ str(len(chan_link_tags)))
if len(chan_description_tags) != 1:
raise FeedStructureError(
"RSS feed's channel has too many or too few"
" description tags; expected 1, was: "
+ str(len(chan_description_tags)))
# if the channel has any items, each item should have
# at least a title or description tag
channel_item_tags = channel.findall('item')
for item in channel_item_tags:
if len(item.findall('title')
+ item.findall('description')) < 1:
raise FeedStructureError(
"An item in the RSS feed's channel did not"
" have at least one of a title or a"
" description tag")
else:
raise FeedStructureError(
"RSS feed's channel does not have enough required"
" children; expected >=3, was: "
+ str(len(channel_children)))
else:
raise FeedStructureError(
"RSS feed does not have any children; expected 1 (a channel"
" tag)")
self._validated = TrueRaises:
FeedStructureError: the XML document violates one of the conditions
"""
assert self._tree is not None
# root should be an rss tag
if self._tree.tag != 'rss':
raise FeedStructureError("XML document is not an RSS feed")
# root should have version attribute which equals 2.0
if 'version' in self._tree.attrib:
if self._tree.attrib['version'] != '2.0':
raise FeedStructureError("RSS version is not 2.0")
else:
raise FeedStructureError(
"RSS feed does not have a version attribute")
# root should have one child, which is the channel tag
root_children = list(self._tree)
if len(root_children) > 0:
if len(root_children) > 1:
raise FeedStructureError(
"RSS feed has too many children; expected 1, was: "
+ str(len(root_children)))
else:
if root_children[0].tag != 'channel':
raise FeedStructureError(
"RSS feed does not have a channel tag as its child")
else:
# channel should have at least 3 children, including a
# title, link, and description tagThis method does not set this object's metadata. That is done in
_process_feed().
Raises:
FeedStructureError: the XML document violates one of the conditions
"""
assert self._tree is not None
# root should be an rss tag
if self._tree.tag != 'rss':
raise FeedStructureError("XML document is not an RSS feed")
# root should have version attribute which equals 2.0
if 'version' in self._tree.attrib:
if self._tree.attrib['version'] != '2.0':
raise FeedStructureError("RSS version is not 2.0")
else:
raise FeedStructureError(
"RSS feed does not have a version attribute")
# root should have one child, which is the channel tag
root_children = list(self._tree)
if len(root_children) > 0:
if len(root_children) > 1:
raise FeedStructureError(
"RSS feed has too many children; expected 1, was: "
+ str(len(root_children)))
else:
if root_children[0].tag != 'channel':
raise FeedStructureError(
"RSS feed does not have a channel tag as its child")
else:
Popular castero functions
- castero.__title__
- castero.config._Config
- castero.config.Config
- castero.database.Database
- castero.datafile.DataFile
- castero.downloadqueue.DownloadQueue
- castero.episode.Episode
- castero.feed.Feed
- castero.feed.FeedStructureError
- castero.feeds.Feeds
- castero.helpers
- castero.helpers.is_true
- castero.helpers.sanitize_path
- castero.menus.episodemenu.EpisodeMenu
- castero.menus.queuemenu.QueueMenu
- castero.player.Player
- castero.player.Player.create_instance
- castero.players.mpvplayer.MPVPlayer
- castero.queue.Queue
- castero.subscriptions.Subscriptions